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10-1.Circle and System of Circles
hard
The line $2 x - y +1=0$ is a tangent to the circle at the point $(2,5)$ and the centre of the circle lies on $x-2 y=4$. Then, the radius of the circle is
A
$3 \sqrt{5}$
B
$5 \sqrt{3}$
C
$5 \sqrt{4}$
D
$4 \sqrt{5}$
(JEE MAIN-2021)
Solution

$\left(\frac{h-\frac{(h-4)}{2}}{2-h}\right)(2)=-1$
$h=8$
center $(8,2)$
Radius $\left.=\sqrt{(8-2)^{2}+(2-5)^{2}}=3 \sqrt{5}\right)$
Standard 11
Mathematics