10-1.Circle and System of Circles
hard

The line $2 x - y +1=0$ is a tangent to the circle at the point $(2,5)$ and the centre of the circle lies on $x-2 y=4$. Then, the radius of the circle is

A

$3 \sqrt{5}$

B

$5 \sqrt{3}$

C

$5 \sqrt{4}$

D

$4 \sqrt{5}$

(JEE MAIN-2021)

Solution

$\left(\frac{h-\frac{(h-4)}{2}}{2-h}\right)(2)=-1$

$h=8$

center $(8,2)$

Radius $\left.=\sqrt{(8-2)^{2}+(2-5)^{2}}=3 \sqrt{5}\right)$

Standard 11
Mathematics

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