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Question

$(\mathrm{x}+\mathrm{y})^{\mathrm{n}} \Rightarrow 2^{\mathrm{n}}=4096\quad 2^{10}=1024 	imes 2$

$\Rightarrow 2^{\mathrm{n}}=2^{12} \quad\quad\quad

Vedclass · Accepted Answer

$924$

Vedclass · Answer

$(\mathrm{x}+\mathrm{y})^{\mathrm{n}} \Rightarrow 2^{\mathrm{n}}=4096\quad 2^{10}=1024 	imes 2$

$\Rightarrow 2^{\mathrm{n}}=2^{12} \quad\quad\quad\quad\quad\quad 2^{11}=2048$

$\mathrm{n}=12 \quad\quad\quad\quad\quad\quad\quad\quad 2^{12}=\underline{4096}$

${ }^{12} \mathrm{C}_{6}=\frac{12 	imes 11 	imes 10 	imes 9 	imes 8 	imes 7}{6 	imes 5 	imes 4 	imes 3 	imes 2 	imes 1}$

$= 11 	imes 3 	imes 4 	imes 7$

$= 924$

If the sum of the coefficients in the expansion of $(x+y)^{n}$ is $4096,$ then the greatest coefficient in the expansion is .... .

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