If sum of coefficients in expansion of {(α {x^2} - 2x + 1)^{35}} is equal to sum of coefficients in

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7.Binomial Theorem

hard

If the sum of the coefficients in the expansion of ${(\alpha {x^2} - 2x + 1)^{35}}$ is equal to the sum of the coefficients in the expansion of ${(x - \alpha y)^{35}}$, then $\alpha $=

A

$0$

B

$1$

C

May be any real number

D

No such value exist

Solution

(b) Accordingly, ${(\alpha – 2 + 1)^{35}} = {(1 – \alpha )^{35}}$

==> ${(\alpha – 1)^{35}} = {(1 – \alpha )^{35}} \Rightarrow \alpha = 1$

Standard 11

Mathematics

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