If the sum of the first $n$ terms of a series be $5{n^2} + 2n$, then its second term is
$7$
$17$
$24$
$42$
(b) ${T_2} = {S_2} – {S_1}$
= $5{(2)^2} + 2(2) – \{ 5{(1)^2} + 2(1)\} = 24 – 7 = 17$.
If $a,\;b,\;c$ are in $A.P.$, then $\frac{1}{{bc}},\;\frac{1}{{ca}},\;\frac{1}{{ab}}$ will be in
Find the $25^{th}$ common term of the following $A.P.'s$
$S_1 = 1, 6, 11, …..$
$S_2 = 3, 7, 11, …..$
The sum of numbers from $250$ to $1000$ which are divisible by $3$ is
The value of $x$ satisfying ${\log _a}x + {\log _{\sqrt a }}x + {\log _{3\sqrt a }}x + ………{\log _{a\sqrt a }}x = \frac{{a + 1}}{2}$ will be
If the ratio of the sum of $n$ terms of two $A.P.'s$ be $(7n + 1):(4n + 27)$, then the ratio of their ${11^{th}}$ terms will be
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