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8. Sequences and Series
easy
If the ${9^{th}}$ term of an $A.P.$ is $35$ and ${19^{th}}$ is $75$, then its ${20^{th}}$ terms will be
A
$78$
B
$79$
C
$80$
D
$81$
Solution
(b) ${T_9} = a + 8d = 35$ and ${T_{19}} = a + 18d = 75$
Solving the equations, we get $d = 4$ and $a = 3$
Hence ${20^{th}}$ term of $A.P.$ ,
$a + 19d = 3 + 19 \times 4 = 79$.
Standard 11
Mathematics