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8. Sequences and Series
medium
The sum of all two digit numbers which, when divided by $4$, yield unity as a remainder is
A
$1190$
B
$1197$
C
$1210$
D
None of these
Solution
(c) The given numbers are $13, 17, ….. 97.$
This is an $AP$ with first term $13$ and common difference $4$.
Let the number of terms be $n$.
Then $97 = 13 + (n – 1)4$
$ \Rightarrow $ $4n = 88$
$ \Rightarrow $ $n = 22$
Therefore the sum of the numbers
$ = \frac{{22}}{2}[13 + 97] = 11(110) = 1210$.
Standard 11
Mathematics