If there is a positive error of 50% in measurement of velocity of a body, then error in measurement

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1.Units, Dimensions and Measurement

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If there is a positive error of $50\%$ in the measurement of velocity of a body, then the error in the measurement of kinetic energy is .............. $\%$

A

$25$

B

$50$

C

$100$

D

$125$

Solution

(d) Kinetic energy $E = \frac{1}{2}m{v^2}$

$\therefore \,\,\,\frac{{\Delta E}}{E} \times 100 = \frac{{{{v'}^2} – {v^2}}}{{{v^2}}} \times 100$

$ = [{(1.5)^2} – 1] \times 100$

$\therefore \,\,\frac{{\Delta E}}{E} \times 100 = 125\% $

Standard 11

Physics

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