Gujarati
3-1.Vectors
medium

If two forces of $5 \,N$ each are acting along $X$ and $Y$ axes, then the magnitude and direction of resultant is

A

$5\sqrt 2 ,\,\,\pi /3$

B

$5\sqrt 2 ,\,\,\pi /4$

C

$ - 5\sqrt 2 ,\,\,\pi /3$

D

$ - 5\sqrt 2 ,\,\,\pi /4$

Solution

(b) $|\overrightarrow F | = \sqrt {{5^2} + {5^2}} = 5\sqrt 2 \;N.$ and $\tan \theta = \frac{5}{5}$=1

$ \Rightarrow \theta = \pi /4.$

Standard 11
Physics

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