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3-1.Vectors
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If two forces of $5 \,N$ each are acting along $X$ and $Y$ axes, then the magnitude and direction of resultant is
A
$5\sqrt 2 ,\,\,\pi /3$
B
$5\sqrt 2 ,\,\,\pi /4$
C
$ - 5\sqrt 2 ,\,\,\pi /3$
D
$ - 5\sqrt 2 ,\,\,\pi /4$
Solution

(b) $|\overrightarrow F | = \sqrt {{5^2} + {5^2}} = 5\sqrt 2 \;N.$ and $\tan \theta = \frac{5}{5}$=1
$ \Rightarrow \theta = \pi /4.$
Standard 11
Physics