વિધુતચુંબકીય તરંગમાં વિધુતક્ષેત્ર અને ચુંબકીય | vedclass

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Question

$\hat{ E }=\hat{ k }$

$\overrightarrow{ B }=2 \hat{ i }-2 \hat{ j } \Rightarrow \hat{ B }=\frac{\overrightarrow{ B }}{| B |}=\frac{2 \hat{ i }-2 \h

Vedclass · Accepted Answer

$\frac{1}{\sqrt{2}}(\hat{ i }+\hat{j})$

Vedclass · Answer

$\hat{ E }=\hat{ k }$

$\overrightarrow{ B }=2 \hat{ i }-2 \hat{ j } \Rightarrow \hat{ B }=\frac{\overrightarrow{ B }}{| B |}=\frac{2 \hat{ i }-2 \hat{ j }}{2 \sqrt{2}}$

$\Rightarrow \hat{ B }=\frac{1}{\sqrt{2}}(\hat{ i }-\hat{j})$

Direction of wave propagation $=\hat{ C }=\hat{ E } 	imes \hat{ B }$

$\hat{ C }=\hat{ k } 	imes\left[\frac{1}{\sqrt{2}}(\hat{ i }-\hat{ j })ight]$

$\hat{ C }=\frac{1}{\sqrt{2}}(\hat{ k } 	imes \hat{ i }-\hat{ k } 	imes \hat{ j })$

$\hat{ C }=\frac{1}{\sqrt{2}}(\hat{ i }+\hat{ j })$

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