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14.Probability
normal
In a regular $15$ -sided polygon with all its diagonals drawn, a diagonal is chosen at random. The probability that it is neither a shortest diagonal nor a longest diagonal is
A
$\frac{2}{3}$
B
$\frac{5}{6}$
C
$\frac{8}{9}$
D
$\frac{8}{9}$
(KVPY-2020)
Solution
(a)
Total number of diagonals of $15$ sided polygons
$={ }^{15} C_2-15=\frac{15 \times 14}{2}-15=90$
$\therefore$ Number of total shortest digonals $=15$
And number of longest digonals $=15$
$\therefore$ 'he probability that the selected diagonal is neither shortest nor longest
$=\frac{90-30}{90}=\frac{60}{90}=\frac{2}{3}$
Standard 11
Mathematics