Gujarati
14.Probability
normal

In a regular $15$ -sided polygon with all its diagonals drawn, a diagonal is chosen at random. The probability that it is neither a shortest diagonal nor a longest diagonal is

A

$\frac{2}{3}$

B

$\frac{5}{6}$

C

$\frac{8}{9}$

D

$\frac{8}{9}$

(KVPY-2020)

Solution

(a)

Total number of diagonals of $15$ sided polygons

$={ }^{15} C_2-15=\frac{15 \times 14}{2}-15=90$

$\therefore$ Number of total shortest digonals $=15$

And number of longest digonals $=15$

$\therefore$ 'he probability that the selected diagonal is neither shortest nor longest

$=\frac{90-30}{90}=\frac{60}{90}=\frac{2}{3}$

Standard 11
Mathematics

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