7.Binomial Theorem
easy

${\left( {{x^2} - 2x} \right)^{10}}$ के विस्तार में ${x^{16}}$ का गुणांक है

A

$-1680$

B

$1680$

C

$3360$

D

$6720$

Solution

${({x^2} – 2x)^{10}}$ के प्रसार में ${x^{16}}$ का गुणांक

= ${x^{10}}{(x – 2)^{10}}$के प्रसार में ${x^{16}}$ का गुणांक

= ${(x – 2)^{10}}$ के प्रसार में ${x^6}$ का गुणांक

=  $^{10}{C_4}{.2^4},\,\,\,\,\left( {\,\,{T_{r + 1}} = {\,^n}{C_r}{x^{n – r}}{a^r}} \right)$

$ = 210 \times 16 = 3360$.

Standard 11
Mathematics

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