In the relation $y = a\cos (\omega t - kx)$, the dimensional formula for $k$ is
In the relation $y = a\cos (\omega t - kx)$, the dimensional formula for $k$ is
- A
$[{M^0}{L^{ - 1}}{T^{ - 1}}]$
- B
$[{M^0}L{T^{ - 1}}]$
- C
$[{M^0}{L^{ - 1}}{T^0}]$
- D
$[{M^0}LT]$
Similar Questions
The physical quantity $'$Energy Density$'$ has same dimensional formula as
The physical quantity $'$Energy Density$'$ has same dimensional formula as
In the relation : $\frac{d y}{d x}=2 \omega \sin \left(\omega t+\phi_0\right)$ the dimensional formula for $\left(\omega t+\phi_0\right)$ is :
In the relation : $\frac{d y}{d x}=2 \omega \sin \left(\omega t+\phi_0\right)$ the dimensional formula for $\left(\omega t+\phi_0\right)$ is :
What is dimensional analysis ? Write limitation of dimensional analysis.
What is dimensional analysis ? Write limitation of dimensional analysis.
The dimension of $\frac{1}{{\sqrt {{\varepsilon _0}{\mu _0}} }}$ is that of
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The dimensional formula of permeability of free space $\mu_0$ is
The dimensional formula of permeability of free space $\mu_0$ is
- [AIIMS 2003]