India plays two matches each with West Indies and Australia. In any match probabilities of India get

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14.Probability

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India plays two matches each with West Indies and Australia. In any match the probabilities of India getting point $0, 1$ and $2$ are $0.45, 0.05$ and $0.50$ respectively. Assuming that the outcomes are independents, the probability of India getting at least $7$ points is

A

$0.8750$

B

$0.0875$

C

$0.0625$

D

$0.0250$

(IIT-1992)

Solution

(b) Matches played by India are four. Maximum points in any match are $2$.

$\therefore $ Maximum points in four matches can be $8$ only.

Therefore probability $(P) = p(7) + p(8)$

$p(7) = {}^4{C_1}(0.05){(0.5)^3} = 0.0250$

$p(8) = {(0.5)^4} = 0.0625$

$ \Rightarrow P = 0.0875$.

Standard 11

Mathematics

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