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2. Electric Potential and Capacitance
easy
Kinetic energy of an electron accelerated in a potential difference of $100\, V$ is
A
$1.6 \times {10^{ - 17}}$ $J$
B
$1.6 \times {10^{21}}$ $J$
C
$1.6 \times {10^{ - 29}}$ $J$
D
$1.6 \times {10^{ - 34}}$ $J$
Solution
(a) By using $KE = QV$ $==>$ $KE = 1.6 × 10^{-19} × 100$
$= 1.6 × 10^{-17} \,J$
Standard 12
Physics