8. Sequences and Series
hard

જો  $a_1 , a_2, a_3, .... , a_n$ એ સમાંતર શ્રેણીમાં હોય અને જો $a_3 + a_7 + a_{11} + a_{15} = 72$ ,તો પ્રથમ  $17$ પદનો સરવાળો મેળવો.

A

$306$

B

$204$

C

$153$

D

$612$

(JEE MAIN-2016)

Solution

$\begin{array}{l}
{a_3} + {a_7} + {a_{11}} + {a_{15}} = 72\\
\left( {{a_3} + {a_{15}}} \right) + \left( {{a_7} + {a_{11}}} \right) = 72\\
{a_3} + {a_{15}} + {a_7} + {a_{11}} = \left( {{a_1} + {a_{17}}} \right)
\end{array}$

$\begin{array}{l}
{a_1} + {a_{17}} = 36\\
{S_{17}} = \frac{{17}}{2}\left[ {{a_1} + {a_{17}}} \right] = 17 \times 18 = 306
\end{array}$

Standard 11
Mathematics

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