Let $p$ and $q$ be two Statements. Amongst the following, the Statement that is equivalent to $p \to q$ is

Negation of the compound proposition : If the examination is difficult, then I shall pass if I study hard

Negation of $p \wedge (\sim q \vee \sim r)$ is -

The negation of the statement $''96$ is divisible by $2$ and $3''$ is

The statement $(\sim( p \Leftrightarrow \sim q )) \wedge q$ is :

Let $p$ and $q$ be two statements.Then $\sim( p \wedge( p \Rightarrow \sim q ))$ is equivalent to