Let *, square in{wedge, vee} be such that the | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$(\mathrm{p} \wedge \sim \mathrm{q}) \rightarrow(\mathrm{p} \vee \mathrm{q})$ is tautology

$p$
			$q$
			$\sim \mathrm{q}$
			$\mathrm{p} \w

Vedclass · Accepted Answer

$*=\wedge, \square=\vee$

Vedclass · Answer

$(\mathrm{p} \wedge \sim \mathrm{q}) \rightarrow(\mathrm{p} \vee \mathrm{q})$ is tautology

$p$
			$q$
			$\sim \mathrm{q}$
			$\mathrm{p} \wedge \sim \mathrm{q}$
			$\mathrm{p} \vee \mathrm{q}$
			$(\mathrm{p} \wedge \sim \mathrm{q}) \rightarrow(\mathrm{p} \vee \mathrm{q})$

$T$
			$T$
			$F$
			$F$
			$T$
			$T$

$T$
			$F$
			$T$
			$T$
			$T$
			$T$

$F$
			$T$
			$F$
			$F$
			$T$
			$T$

$F$
			$F$
			$T$
			$F$
			$F$
			$T$

Let $, \square \in\{\wedge, \vee\}$ be such that the Boolean expression $(\mathrm{p} \sim \mathrm{q}) \Rightarrow(\mathrm{p} \square \mathrm{q})$ is a tautology. Then :

Similar Questions

$\sim p \wedge q$ is logically equivalent to

If $p, q, r$ are simple propositions, then $(p \wedge q) \wedge (q \wedge r)$ is true then

Negation of the compound proposition : If the examination is difficult, then I shall pass if I study hard

Statement $-1 :$ $\sim (p \leftrightarrow \sim q)$ is equivalent to $p\leftrightarrow q $

Statement $-2 :$ $\sim (p \leftrightarrow \sim q)$ s a tautology

Negation of $p \wedge( q \wedge \sim( p \wedge q ))$ is

Let $*, \square \in\{\wedge, \vee\}$ be such that the Boolean expression $(\mathrm{p} * \sim \mathrm{q}) \Rightarrow(\mathrm{p} \square \mathrm{q})$ is a tautology. Then :