Let,$p$ : Ramesh listens to music.
$q :$ Ramesh is out of his village
$r :$ It is Sunday
$s :$ It is Saturday
Then the statement "Ramesh listens to music only if he is in his village and it is Sunday or Saturday"can be expressed as.
$(\sim q) \wedge(r \vee s)) \Rightarrow p$
$(q \wedge(r \vee s)) \Rightarrow p$
$p \Rightarrow(q \wedge(r \vee s))$
$p \Rightarrow((\sim q ) \wedge( r \vee s ))$
$\sim (p \wedge q)$ is equal to .....
Contrapositive of the statement 'If two numbers are not equal, then their squares are not equal', is
If $(p\; \wedge \sim r) \Rightarrow (q \vee r)$ is false and $q$ and $r$ are both false, then $p$ is
If the truth value of the statement $p \to \left( { \sim q \vee r} \right)$ is false $(F)$, then the truth values of the statement $p, q, r$ are respectively
Which of the following pairs are not logically equivalent ?