Let $\mathrm{a}_{1}, \mathrm{a}_{2}, \mathrm{a}_{3}, \ldots$ be an $A.P.$ If $\frac{a_{1}+a_{2}+\ldots+a_{10}}{a_{1}+a_{2}+\ldots+a_{p}}=\frac{100}{p^{2}}, p \neq 10$, then $\frac{a_{11}}{a_{10}}$ is equal to :

  • [JEE MAIN 2021]
  • A

    $\frac{19}{21}$

  • B

    $\frac{100}{121}$

  • C

    $\frac{21}{19}$

  • D

    $\frac{121}{100}$

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