Let $\alpha, \beta$ be two roots of the equation $x^{2}+(20)^{\frac{1}{4}} x+(5)^{\frac{1}{2}}=0$. Then $\alpha^{8}+\beta^{8}$ is equal to:

The equation $x^2-4 x+[x]+3=x[x]$, where $[x]$ denotes the greatest integer function, has:

For the equation $|{x^2}| + |x| - 6 = 0$, the roots are

If $\log _{(3 x-1)}(x-2)=\log _{\left(9 x^2-6 x+1\right)}\left(2 x^2-10 x-2\right)$, then $x$ equals

If $a < 0$ then the inequality $a{x^2} - 2x + 4 > 0$ has the solution represented by

The real roots of the equation ${x^2} + 5|x| + \,\,4 = 0$ are