4-2.Quadratic Equations and Inequations
normal

Let $a$ ,$b$, $c$ , $d$ , $e$ be five numbers satisfying the system of equations

                            $2a + b + c + d + e = 6$
                            $a + 2b + c + d + e = 12$
                            $a + b + 2c + d + e = 24$
                            $a + b + c + 2d + e = 48$
                            $a + b + c + d + 2e = 96$ ,

then $|c|$ is equal to 

A

$6$

B

$7$

C

$8$

D

$25$

Solution

adding all we have $6(a + b + c + d + e) = 6.31$

$\sum {a\, = 31\, \Rightarrow \,c\, = \, – 7} $

Standard 11
Mathematics

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