3 and 4 .Determinants and Matrices
hard

ધારો કે $A =\left[ a _{i j}\right]$ એ $3$ કક્ષાવાળો એવો ચોરસ શ્રેણીક છે કે જેથી પ્રત્યેક $i, j=1,2,3$ માટે $a _{i j}=2 j-i$ થાય. તો શ્રેણિક $A ^{2}+ A ^{3}+\ldots+ A ^{10}=\dots\dots\dots$

A

$\left(\frac{3^{10}-3}{2}\right) A$

B

$\left(\frac{3^{10}-1}{2}\right) A$

C

$\left(\frac{3^{10}+1}{2}\right) A$

D

$\left(\frac{3^{10}+3}{2}\right) A$

(JEE MAIN-2022)

Solution

$A=\left(\begin{array}{lll}1 & 2 & 2^{2} \\ 1 / 2 & 1 & 2 \\ 1 / 2^{2} & 1 / 2 & 1\end{array}\right)$

$A^{2}=3 A$

$A ^{3}=3^{2} A$

$A ^{2}+ A ^{3}+\ldots A ^{10}$

$=3 A +3^{2} A +\ldots+3^{9} A =\frac{3\left(3^{9}-1\right)}{3-1} A$

$=\frac{3^{10}-3}{2} A$

Standard 12
Mathematics

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