Let a be the largest real root and b be the s | vedclass

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Question

(b)

$x ^6-6 x ^5+15 x ^4-20 x ^3+15 x ^2-6 x +1=0$ $( x -1)^6=0$

All roots are equal and are equal to 1 $	herefore a =1, b =1$

$	herefore \

Vedclass · Accepted Answer

$\frac{2}{3}$

Vedclass · Answer

(b)

$x ^6-6 x ^5+15 x ^4-20 x ^3+15 x ^2-6 x +1=0$ $( x -1)^6=0$

All roots are equal and are equal to 1 $	herefore a =1, b =1$

$	herefore \frac{a^2+b^2}{a+b+1}=\frac{2}{3}$

Let $a$ be the largest real root and $b$ be the smallest real root of the polynomial equation $x^6-6 x^5+15 x^4-20 x^3+15 x^2-6 x+1=0$ Then $\frac{a^2+b^2}{a+b+1}$ is

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