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1.Relation and Function
hard
ધારોકે $R =\{ a , b , c , d , e \}$ અને $S =\{1,2,3,4\}$ તો $f( a ) \neq 1$ હોય તેવા $f: R \rightarrow S$ વ્યાપ્ત વિધેયોની સંખ્યા $.........$ છે.
A
$180$
B
$170$
C
$160$
D
$150$
(JEE MAIN-2023)
Solution
Total onto function
$\frac{[5}{\left\lfloor{3}\lfloor 2\right.} \times\lfloor 4=240$
Now when $f(a)=1$
$\lfloor 4+\frac{\lfloor 4}{\lfloor 2\lfloor 2} \times\lfloor 3=24+36=60$
so required $f ^{ n }=240-60=180$
Standard 12
Mathematics
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