Let U be universal set and A cup B cup C = U . Then { (A - B) cup (B - C) cup (C - A)} ' is equa

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1.Set Theory

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Let $U$ be the universal set and $A \cup B \cup C = U$. Then $\{ (A - B) \cup (B - C) \cup (C - A)\} '$ is equal to

A

$A \cup B \cup C$

B

$A \cup (B \cap C)$

C

$A \cap B \cap C$

D

$A \cap (B \cup C)$

Solution

(c) From Venn-Euler's Diagram,

Clearly, $\{ (A – B) \cup (B – C) \cup (C – A)\} ' = A \cap B \cap C$.

Standard 11

Mathematics

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