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1.Set Theory
easy
જો બે ગણો $A$ અને $B$ છે કેે જેથી$n(A) = 0.16,\,n(B) = 0.14,\,n(A \cup B) = 0.25$. તો $n(A \cap B) =$
A
$0.3$
B
$0.5$
C
$0.05$
D
એકપણ નહી.
Solution
(c) $n(A \cup B) = n(A) + n(B) – n(A \cap B)$
$0.25 = 0.16 + 0.14 – n(A \cap B)$
==> $n(A \cap B) = 0.30 – 0.25 = 0.05$.
Standard 11
Mathematics