1.Set Theory
easy

જો બે ગણો $A$ અને $B$ છે કેે જેથી$n(A) = 0.16,\,n(B) = 0.14,\,n(A \cup B) = 0.25$. તો $n(A \cap B)  =$

A

$0.3$

B

$0.5$

C

$0.05$

D

એકપણ નહી.

Solution

(c) $n(A \cup B) = n(A) + n(B) – n(A \cap B)$

$0.25 = 0.16 + 0.14 – n(A \cap B)$

==> $n(A \cap B) = 0.30 – 0.25 = 0.05$.

Standard 11
Mathematics

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