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જો $X = \{ 1,\,2,\,3,\,4,\,5\} $ અને $Y = \{ 1,\,3,\,5,\,7,\,9\} $ તો નીચેના પૈકી . . . એ $X$ થી $Y$ પરનો સંબંધ ર્દશાવે.
${R_1} = \{ (x,\,y)|y = 2 + x,\,x \in X,\,y \in Y\} $
${R_2} = \{ (1,\,1),\,(2,\,1),\,(3,\,3),\,(4,\,3),\,(5,\,5)\} $
${R_3} = \{ (1,\,1),\,(1,\,3)(3,\,5),\,(3,\,7),\,(5,\,7)\} $
(B) અને (C) બંને
Solution
$R_1=\{(x, y): y=2+x, x \in X, y \in Y\}$
$x=1 \rightarrow y=1+2=3$
$x=2 \rightarrow y=2+2=4$
$x=3 \rightarrow y=3+2=5$
$x=4 \rightarrow y=4+2=6$
$x=5 \rightarrow y=5+2=7$
$R=\{(1,3),(2,4),(3,5),(4,6),(5,7)\}$
Here in $(4,6)$ ,$6$ does not belong to either $X$or$Y$
So $R_1$ is not a relation between $X$ and $Y$
In $R _4$, since it contains an element $(7,9)$ which relates set $Y$ to set $Y$, while rest elements relate set $X$ to $Y$.
$\therefore R _4$ is not a relation between $X$ and $Y$