Let {R_1} be a relation defined by {R_1} = { | vedclass

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(b) For any $a \in R$, we have $a \ge a,$ Therefore the relation $R$ is reflexive but it is not symmetric as $(2, 1)$ $ \in R$ but $(1, 2)$ $ 
otin R

Vedclass · Accepted Answer

Reflexive, transitive but not symmetric

Vedclass · Answer

(b) For any $a \in R$, we have $a \ge a,$ Therefore the relation $R$ is reflexive but it is not symmetric as $(2, 1)$ $ \in R$ but $(1, 2)$ $ 
otin R$. The relation $R$ is transitive also, because $(a,b) \in R,(b,c) \in R$ imply that $a \ge b$ and $b \ge c$ which is turn imply that $a \ge c$.

Let ${R_1}$ be a relation defined by ${R_1} = \{ (a,\,b)|a \ge b,\,a,\,b \in R\} $. Then ${R_1}$ is

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