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3 and 4 .Determinants and Matrices
hard
Let $\mathrm{A}(-1,1)$ and $\mathrm{B}(2,3)$ be two points and $\mathrm{P}$ be a variable point above the line $A B$ such that the area of $\triangle \mathrm{PAB}$ is $10$ . If the locus of $\mathrm{P}$ is $\mathrm{ax}+\mathrm{by}=15$, then $5 a+2 b$ is :
A
$-\frac{12}{5}$
B
$-\frac{6}{5}$
C
$4$
D
$6$
(JEE MAIN-2024)
Solution

$\frac{1}{2}\left|\begin{array}{lll}\mathrm{h} & \mathrm{k} & 1 \\ -1 & 1 & 1 \\ 2 & 3 & 1\end{array}\right|=10$
$ -2 x+3 y=25 $
$ -\frac{6}{5} x+\frac{9}{5} y=15 $
$ a=-\frac{6}{5}, b=\frac{9}{5} $
$ 5 a=-6,2 b=\frac{18}{5}$
Standard 12
Mathematics