Gujarati
3 and 4 .Determinants and Matrices
normal

माना की $\quad P_1=I=\left[\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array}\right], \quad P_2=\left[\begin{array}{lll}1 & 0 & 0 \\ 0 & 0 & 1 \\ 0 & 1 & 0\end{array}\right], \quad P_3=\left[\begin{array}{lll}0 & 1 & 0 \\ 1 & 0 & 0 \\ 0 & 0 & 1\end{array}\right], \quad P_4=\left[\begin{array}{lll}0 & 1 & 0 \\ 0 & 0 & 1 \\ 1 & 0 & 0\end{array}\right], \quad P_5=\left[\begin{array}{lll}0 & 0 & 1 \\ 1 & 0 & 0 \\ 0 & 1 & 0\end{array}\right]$,

$P_6=\left[\begin{array}{lll}0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0\end{array}\right]$ और $X=\sum_{k=1}^6 P_k\left[\begin{array}{lll}2 & 1 & 3 \\ 1 & 0 & 2 \\ 3 & 2 & 1\end{array}\right] P_k^{\top}$

जहाँ आव्यूह (matrix) $P _{ K }$ के परिवर्त (transpose) को $P _{ K }^{ T }$ से दर्शाया गया है। तब निम्न में से कौन सा (से) विकल्प सहीं है (हैं)?

जहाँ आव्यूह (matrix) $P _{ K }$ के परिवर्त (transpose) को $P _{ E }^{ T }$ से दर्शाया गया है। तब निम्न में से कौन सा (से) विकल्प सहीं है

(हैं)?

$(1)$ $X -30 I$ एक व्युत्क्रमणीय (invertible) आव्यूह है।

$(2)$ $X$ के विकर्ण (diagonal) की प्रविष्टियों (entries) का योग $18$ है

$(3)$यदि $X \left[\begin{array}{l}1 \\ 1 \\ 1\end{array}\right]=\alpha\left[\begin{array}{l}1 \\ 1 \\ 1\end{array}\right]$, तब $\alpha=30$

$(4)$ $X$ एक समित (symmetric) अव्युह हैं

A

$1,2,3$

B

$2,3,4$

C

$1,2,4$

D

$2,4$

(IIT-2019)

Solution

Let $Q=\left[\begin{array}{lll}2 & 1 & 3 \\ 1 & 0 & 2 \\ 3 & 2 & 1\end{array}\right]$

$X=\sum_{k=1}^6\left(P_k Q P_k^T\right)$

$X^T=\sum_{k=1}^6\left(P_k Q P_k^T\right)^T=X .0$

$X$ is symmetric

Let $R=\left[\begin{array}{l}1 \\ 1 \\ 1\end{array}\right]$

$X R=\sum_{1=1}^6 P_k Q P_k^{\top} R \cdot\left[\because P_k{ }^{\top} R=R\right]$

$=\sum_{k=1}^6 P_k Q R \cdot=\left(\sum_{k=1}^6 P_k\right) Q R$

$\begin{array}{l}\sum_{ K =1}^6 P _{ x }=\left[\begin{array}{lll}2 & 2 & 2 \\ 2 & 2 & 2 \\ 2 & 2 & 2\end{array}\right] \quad QR =\left[\begin{array}{l}6 \\ 3 \\ 6\end{array}\right] \\ \Rightarrow XR =\left[\begin{array}{lll}2 & 2 & 2 \\ 2 & 2 & 2 \\ 2 & 2 & 2\end{array}\right]\left[\begin{array}{l}6 \\ 3 \\ 6\end{array}\right]=\left[\begin{array}{l}30 \\ 30 \\ 30\end{array}\right]=30 R \end{array}$

$\Rightarrow \alpha=30 \text {. }$

Trace $X =\operatorname{Trace}\left(\sum_{ K =1}^{\circ} P _{ k } Q F _{ K }^{ T }\right)$

$\begin{array}{l}=\sum_{ K =1}^6 \operatorname{Trace}\left( P _{ x } QP _{ k }^{ T }\right)=6(\text { Irace } Q )=18 \\ x \left[\begin{array}{l}1 \\ 1 \\ 1\end{array}\right]=30\left[\begin{array}{l}1 \\ 1 \\ 1\end{array}\right] \\ \Rightarrow( X -30 I )\left[\begin{array}{l}1 \\ 1 \\ 1\end{array}\right]= O \Rightarrow| X -30 I |=0 \\ \Rightarrow X -301 \text { is non-imvertible } \\\end{array}$

Standard 12
Mathematics

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