Write Minors and Cofactors of the elements of following determinants: $\left|\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array}\right|$

If ${\Delta _1} = \left| {\begin{array}{*{20}{c}}
  {{b^5}{c^6}\left( {{c^3} – {b^3}} \right)}&{{a^4}{c^6}\left( {{a^3} – {c^3}} \right)}&{{a^4}{b^5}\left( {{b^3} – {a^3}} \right)} \\ 
  {{b^2}{c^3}\left( {{b^6} – {c^6}} \right)}&{a{c^3}\left( {{c^6} – {a^6}} \right)}&{a{b^2}\left( {{a^6} – {b^6}} \right)} \\ 
  {{b^2}{c^3}\left( {{c^3} – {b^3}} \right)}&{a{c^3}\left( {{a^3} – {c^3}} \right)}&{a{b^2}\left( {{b^3} – {a^3}} \right)} 
\end{array}} \right|$ and ${\Delta _2} = \left| {\begin{array}{*{20}{c}}
  a&{{b^2}}&{{c^3}} \\ 
  {{a^4}}&{{b^5}}&{{c^6}} \\ 
  {{a^7}}&{{b^8}}&{{c^9}} 
\end{array}} \right|$ then ${\Delta _1}{\Delta _2}$ is equal to

If value of a third order determinant is $11$, then the value of the square of the determinant formed by the cofactors will be

In the determinant $\left| {\,\begin{array}{*{20}{c}}0&1&{ – 2}\\{ – 1}&0&3\\2&{ – 3}&0\end{array}\,} \right|$, the ratio of the co-factor to its minor of the element $-3$ is

The minors of $ -4$ and  $ 9$  and the co-factors of  $-4$  and $ 9$ in determinant $\,\left| {\,\begin{array}{*{20}{c}}{ – 1}&{ – 2}&3\\{ – 4}&{ – 5}&{ – 6}\\{ – 7}&8&9\end{array}\,} \right|$ are respectively