Let A and B be events for which P(A) = x , P(B) = y, P(A cap B) = z, then P(bar A cap B) equals

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14.Probability

easy

Let $A$ and $B$ be events for which $P(A) = x$, $P(B) = y,$$P(A \cap B) = z,$ then $P(\bar A \cap B)$ equals

A

$(1 - x)\,y$

B

$1 - x + \,y$

C

$y -z$

D

$1 - x + y - z$

Solution

(c) $P(\bar A\, \cap B)\, = P(B) – P(A \cap B) = y – z.$

Standard 11

Mathematics

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