- Home
- Standard 11
- Mathematics
14.Probability
medium
माना $A$ तथा $B$ दो घटनायें है तथा $P(A') = 0.3$, $P(B) = 0.4,\,P(A \cap B') = 0.5$ तब $P(A \cup B') =$
A
$0.5$
B
$0.8$
C
$1$
D
$0.1$
Solution
(b) $P(A') = 0.3$, $\therefore$ , $P(A) = 0.7$
$P(B') = 0.6$, $\therefore $ $P(B) = 0.4$ और $P(A \cap B') = 0.5$
$\therefore $ $P(A \cup B') = P(A) + P(B') – P(A \cap B')$
$= 0.7 + 0.6 -0.5 = 0.8$.
Standard 11
Mathematics
