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1.Relation and Function
easy
Let $A = \{ 2,\,4,\,6,\,8\} $. $A$ relation $R$ on $A$ is defined by $R = \{ (2,\,4),\,(4,\,2),\,(4,\,6),\,(6,\,4)\} $. Then $R$ is
A
Anti-symmetric
B
Reflexive
C
Symmetric
D
Transitive
Solution
(c) Given $A = \{2, 4, 6, 8\}$; $R = \{(2, 4)(4, 2) (4, 6) (6, 4)\}$
$(a, b)$ $\therefore$ $R$==> $(b, a)$
$\therefore$ $R$ and also ${R^{ – 1}} = R$.
Hence, $R$ is symmetric.
Standard 12
Mathematics
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