Let $[ {\varepsilon _0} ]$ denote the dimensional formula of the permittivity of vacuum. If $M =$ mass, $L=$ length, $T =$ time and $A=$ electric current, then:
- [JEE MAIN 2013]
- A$[ {\varepsilon _0} ]=[M^{-1}L^{-3}T^2A]$
- B$[ {\varepsilon _0} ]=[M^{-1}L^{-3}T^4A^2]$
- C$[ {\varepsilon _0} ]=[M^{-1}L^2T^{-1}A^{-2}]$
- D$[ {\varepsilon _0} ]=[M^{-1}L^2T^{-1}A]$
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