Let determinant of a 3 × 3 matrix A be 6 then B is a matrix defined by B = 5{A^2} . Then det

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3 and 4 .Determinants and Matrices

hard

Let the determinant of a $3 \times 3$ matrix A be 6 then $B$ is a matrix defined by $B = 5{A^2}$. Then det of $B$ is

A

$4500$

B

$100$

C

$80$

D

None of these

Solution

(a) Given $|A| = 6$ and $B = 5{A^2}$
==> $|B| = 125|A{|^2} = 125 \times 36 = 4500$.

Standard 12

Mathematics

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