Let the function $f$ be defined by $f(x) = \frac{{2x + 1}}{{1 - 3x}}$, then ${f^{ - 1}}(x)$ is
Let the function $f$ be defined by $f(x) = \frac{{2x + 1}}{{1 - 3x}}$, then ${f^{ - 1}}(x)$ is
- A
$\frac{{x - 1}}{{3x + 2}}$
- B
$\frac{{3x + 2}}{{x - 1}}$
- C
$\frac{{x + 1}}{{3x - 2}}$
- D
$\frac{{2x + 1}}{{1 - 3x}}$
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- [JEE MAIN 2021]
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