Let the ratio of the fifth term from the begi | vedclass

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Question

$\frac{T_{5}}{T_{n-1}}=\frac{{ }^{n} C_{4}\left(2^{1 / 4}\right)^{n-4}\left(3^{-1 / 4}\right)^{4}}{\left(2^{1 / 4}\right)^{4}\left(3^{-1 / 4}\right)^{

Vedclass · Accepted Answer

$84$

Vedclass · Answer

$\frac{T_{5}}{T_{n-1}}=\frac{{ }^{n} C_{4}\left(2^{1 / 4}ight)^{n-4}\left(3^{-1 / 4}ight)^{4}}{\left(2^{1 / 4}ight)^{4}\left(3^{-1 / 4}ight)^{n-4}}=\frac{\sqrt[4]{6}}{1}$

$\Rightarrow 2^{\frac{n-8}{4}} 3^{\frac{n-8}{4}}=6^{1 / 4}$

$\Rightarrow 6^{n-3}=6$

$\Rightarrow n-8=1 \Rightarrow n=9$

$T_{6}={ }^{9} C_{5}\left(2^{1 / 4}ight)^{4}\left(3^{-1 / 4}ight)^{5}=\frac{84}{\sqrt[4]{3}}$

$	herefore \alpha=84$

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