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3-1.Vectors
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दो सदिशों $6\hat i + 7\hat j$ तथा $3\hat i + 4\hat j$ के योग से प्राप्त सदिश का परिमाण है
A
$\sqrt {136} $
B
$\sqrt {13.2} $
C
$\sqrt {202} $
D
$\sqrt {160} $
Solution
(c) $\mathop R\limits^ \to = \mathop A\limits^ \to + \mathop B\limits^ \to $ = $6\hat i + 7\hat j + 3\hat i + 4\hat j$= $9\hat i + 11\hat j$
$|\overrightarrow R |\; = \;\sqrt {{9^2} + {{11}^2}} = \sqrt {81 + 121} = \sqrt {202} $
Standard 11
Physics
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