Number of solutions of equation $|x^2 -2|x||$ = $2^x$ , is
Number of solutions of equation $|x^2 -2|x||$ = $2^x$ , is
- A
$1$
- B
$2$
- C
$3$
- D
$4$
Similar Questions
All the points $(x, y)$ in the plane satisfying the equation $x^2+2 x \sin (x y)+1=0$ lie on
All the points $(x, y)$ in the plane satisfying the equation $x^2+2 x \sin (x y)+1=0$ lie on
- [KVPY 2011]
If $x$ is real, then the value of $\frac{{{x^2} + 34x - 71}}{{{x^2} + 2x - 7}}$ does not lie between
If $x$ is real, then the value of $\frac{{{x^2} + 34x - 71}}{{{x^2} + 2x - 7}}$ does not lie between
The number of real solutions of the equation $|x{|^2}$-$3|x| + 2 = 0$ are
The number of real solutions of the equation $|x{|^2}$-$3|x| + 2 = 0$ are
- [IIT 1982]
$\{ x \in R:|x - 2|\,\, = {x^2}\} = $
$\{ x \in R:|x - 2|\,\, = {x^2}\} = $
If $\alpha,\beta,\gamma, \delta$ are the roots of $x^4-100x^3+2x^2+4x+10 = 0$ then $\frac{1}{\alpha}+\frac{1}{\beta}+\frac{1}{\gamma}+\frac{1}{\delta}$ is equal to :-
If $\alpha,\beta,\gamma, \delta$ are the roots of $x^4-100x^3+2x^2+4x+10 = 0$ then $\frac{1}{\alpha}+\frac{1}{\beta}+\frac{1}{\gamma}+\frac{1}{\delta}$ is equal to :-