If $\alpha, \beta $ and $\gamma$ are the roots of the equation $2{x^3} - 3{x^2} + 6x + 1 = 0$, then ${\alpha ^2} + {\beta ^2} + {\gamma ^2}$ is equal to

  • A

    -$\frac{{15}}{4}$

  • B

    $\frac{{15}}{4}$

  • C

    $\frac{9}{4}$

  • D

    $4$

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