સાબિત કરો કે નિશ્ચાયક $\left|\begin{array}{ccc}x & \sin \theta & \cos \theta \\ -\sin \theta & -x & 1 \\ \cos \theta & 1 & x\end{array}\right|$ નું મૂલ્ય $\theta$ થી મુક્ત છે. 

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$\Delta=\left|\begin{array}{ccc}x & \sin \theta & \cos \theta \\ -\sin \theta & -x & 1 \\ \cos \theta & 1 & x\end{array}\right|$

$=x\left(x^{2}-1\right)-\sin \theta(-x \sin \theta-\cos \theta)+\cos \theta(-\sin \theta+x \cos \theta)$

$=x^{3}-x+x \sin ^{2} \theta+\sin \theta \cos \theta-\sin \theta \cos \theta+x \cos ^{2} \theta$

$=x^{3}-x+x\left(\sin ^{2} \theta+\cos ^{2} \theta\right)$

$=x^{3}-x+x$

$\left.=x^{3} \quad \text { (Independent of } \theta\right)$

Hence, $\Delta$ is independent of $\theta$

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$\theta \in(0,4 \pi)$ ની કેટલી કિમંતો માટે સમીકરણ સંહતિ $3(\sin 3 \theta) x-y+z=2$, $3(\cos 2 \theta) x+4 y+3 z=3$, $6 x+7 y+7 z=9$ ને એકપણ ઉકેલ ન હોય.

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