Radioactive element decays to form a stable nuclide, then rate of decay of reactant left( {frac{{dN}

English

Gujarati

Hindi

13.Nuclei

medium

Radioactive element decays to form a stable nuclide, then the rate of decay of reactant $\left( {\frac{{dN}}{{dt}}} \right)$ will vary with time $(t) $ as shown in figure

A

B

C

D

Solution

(c) $N = {N_0}{e^{ – \lambda t}}$==> $\frac{{dN}}{{dt}} = – {N_0}\lambda {e^{ – \lambda t}}$

$i.e.$ Rate of decay $\left( {\frac{{dN}}{{dt}}} \right)$ varies exponentially with time $(t).$

Standard 12

Physics

Share

Similar Questions

If $10\%$ of a radioactive material decays in $5\, days$ then the amount of the original material left after $20\, days$ is approximately ………. $\%$

medium

A piece of bone of an animal from a ruin is found to have $^{14}C$ activity of $12$ disintegrations per minute per gm of its carbon content. The $^{14}C$ activity of a living animal is $16$ disintegrations per minute per gm. How long ago nearly did the animal die? …………$years$ (Given halflife of $^{14}C$ is $t_{1/2} = 5760\,years$ )

medium

(JEE MAIN-2014)

The half-life of radium is about $1600$ years. Of $100\, g$ of radium existing now, $25\, g$ will remain unchanged after ………. $years$

medium

(AIPMT-2004)

A radioactive material decays by simultaneous emission of two particles with respective half lives $1620$ and $810$ years. The time (in years) after which one- fourth of the material remains is

medium

(IIT-1995)

During mean life of a radioactive element, the fraction that disintegrates is

medium