Solution of the equation $\sqrt {x + 3 - 4\sqrt {x - 1} } + \sqrt {x + 8 - 6\sqrt {x - 1} } = 1$ is
Solution of the equation $\sqrt {x + 3 - 4\sqrt {x - 1} } + \sqrt {x + 8 - 6\sqrt {x - 1} } = 1$ is
- A
$x \in \left[ {4,9} \right]$
- B
$x \in \left[ {3,8} \right]$
- C
$x \in \left[ {5,10} \right]$
- D
$x \in \left[ {4,7} \right]$
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