For a real number $x$, let $[x]$ denote the largest integer less than or equal to $x$, and let $\{x\}=x-[x]$. The number of solutions $x$ to the equation $[x]\{x\}=5$ with $0 \leq x \leq 2015$ is

  • [KVPY 2015]
  • A

    $0$

  • B

    $3$

  • C

    $2008$

  • D

    $2009$

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