Solution of the equation ${9^x} - {2^{x + {1 \over 2}}} = {2^{x + {3 \over 2}}} - {3^{2x - 1}}$
Solution of the equation ${9^x} - {2^{x + {1 \over 2}}} = {2^{x + {3 \over 2}}} - {3^{2x - 1}}$
- A
${\log _9}(9/\sqrt 8 )$
- B
${\log _{\left( {9/2} \right)}}(9/\sqrt 8 )$
- C
${\log _e}(9/\sqrt 8 )$
- D
None of these
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