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Mathematical Reasoning
normal
Statement $\left( {p \wedge q} \right) \to \left( {p \vee q} \right)$ is
A
contradiction
B
tautology
C
neither tautology nor contradiction
D
can't say
Solution
i.e. tautology
$p$ | $q$ | ${p \wedge q}$ | $p \vee q$ | $( {p \wedge q \to }$ ${p \vee q})$ |
$T$ | $T$ | $T$ | $T$ | $T$ |
$T$ | $F$ | $F$ | $T$ | $T$ |
$F$ | $T$ | $F$ | $T$ | $T$ |
$F$ | $F$ | $F$ | $F$ | $T$ |
Standard 11
Mathematics