Statement $\left( {p \wedge q} \right) \to \left( {p \vee q} \right)$ is

The expression $ \sim ( \sim p\, \to \,q)$ is logically equivalent to

Among the statements:

$(S1)$ $\quad(( p \vee q ) \Rightarrow r ) \Leftrightarrow( p \Rightarrow r )$

$(S2) \quad(( p \vee q ) \Rightarrow r ) \Leftrightarrow(( p \Rightarrow r ) \vee( q \Rightarrow r ))$

The converse of the statement "If $p < q$, then $p -x < q -x"$ is -

If the truth value of the statement $p \to \left( { \sim q \vee r} \right)$ is false $(F)$, then the truth values of the statement $p, q, r$ are respectively

$(p \to q) \leftrightarrow (q\ \vee  \sim p)$ is