11.Thermodynamics
medium

The $P-V$ diagram of a diatomic ideal gas system going under cyclic process as shown in figure. The work done during an adiabatic process $CD$ is (use $\gamma=1.4$) (in $J$)

A

$-500$

B

$-400$

C

$400$

D

$200$

(JEE MAIN-2021)

Solution

Adiabatic process is from $C$ to $D$

$WD =\frac{ P _{2} V _{2}- P _{1} V _{1}}{1-\gamma}$

$=\frac{P_{D} V_{D}-P_{C} V_{C}}{1-\gamma}$

$=\frac{200(3)-(100)(4)}{1-1.4}$

$=-500\, J$

Standard 11
Physics

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