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11.Thermodynamics
medium
The $P-V$ diagram of a diatomic ideal gas system going under cyclic process as shown in figure. The work done during an adiabatic process $CD$ is (use $\gamma=1.4$) (in $J$)

A
$-500$
B
$-400$
C
$400$
D
$200$
(JEE MAIN-2021)
Solution
Adiabatic process is from $C$ to $D$
$WD =\frac{ P _{2} V _{2}- P _{1} V _{1}}{1-\gamma}$
$=\frac{P_{D} V_{D}-P_{C} V_{C}}{1-\gamma}$
$=\frac{200(3)-(100)(4)}{1-1.4}$
$=-500\, J$
Standard 11
Physics