Acceleration of an electron in an electric field of magnitude 50, V/cm , if e/m value of electron is

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1. Electric Charges and Fields

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The acceleration of an electron in an electric field of magnitude $50\, V/cm$, if $e/m$ value of the electron is $1.76 \times {10^{11}}\,C/kg$, is

A

$8.8 \times {10^{14}}\,m/sec^2$

B

$6.2 \times {10^{13}}\,m/sec^2$

C

$5.4 \times {10^{12}}\,m/sec^2$

D

Zero

Solution

(a) $a = \frac{{eE}}{m} \Rightarrow \,a = 1.76 \times {10^{11}} \times 50 \times {10^2}$ $ = 8.8 \times {10^{14}}\,m/se{c^2}$

Standard 12

Physics

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