Gujarati
1. Electric Charges and Fields
easy

$50\, V/cm$ परिमाण के विद्युत क्षेत्र में एक इलेक्ट्रॉन का त्वरण हेागा  (यदि इलेक्ट्रॉन के लिए $e/m = 1.76 \times {10^{11}}\,C/kg$)

A

$8.8 \times {10^{14}}\,m/sec^2$

B

$6.2 \times {10^{13}}\,m/sec^2$

C

$5.4 \times {10^{12}}\,m/sec^2$

D

Zero

Solution

$a = \frac{{eE}}{m} \Rightarrow \,a = 1.76 \times {10^{11}} \times 50 \times {10^2}$ $ = 8.8 \times {10^{14}}\,m/se{c^2}$

Standard 12
Physics

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